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0=5x^2+36x-96
We move all terms to the left:
0-(5x^2+36x-96)=0
We add all the numbers together, and all the variables
-(5x^2+36x-96)=0
We get rid of parentheses
-5x^2-36x+96=0
a = -5; b = -36; c = +96;
Δ = b2-4ac
Δ = -362-4·(-5)·96
Δ = 3216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3216}=\sqrt{16*201}=\sqrt{16}*\sqrt{201}=4\sqrt{201}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-4\sqrt{201}}{2*-5}=\frac{36-4\sqrt{201}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+4\sqrt{201}}{2*-5}=\frac{36+4\sqrt{201}}{-10} $
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